Using (x-h)^2+(y-h)=r^2
sub in -1 and 2 for h and k
get sqrt of 4 for r
anser is therefore
(x+1)^2+(y-2)=2^2
Have and Wonderful Day,
Danny
3.14 x 1
This makes no sence
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
The equation is: (x+1)^2 +(y+5)^2 = 36
(x - 1)2 + (y + 1)2 = 1
(x-3)2 + (y-1)2 = 42
(x + 1)2 + (y + 5)2 = 36
(x + 2)2 + (y - 2)2 = 1
It is: (x-1)^2 +(y+4)^2 = 4
It is: (x+3)^2+(y-1)^2 = 25