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Perpendicular slope: -2/5

Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14

Perpendicular equation in its general form: 2x+5y+14 = 0

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Q: What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
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What is the equation of the line passing through -2 -3 that is at right angles to the equation 4x plus 3y -5 equals 0 on the Cartesian plane?

The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0


What is the perpendicular distance from the point 2 4 to the straight line equation of y equals 2x plus 10 on the Cartesian plane?

It works out as: 2 times the square root of 5


What is the perpendicular distance from the point of 2 4 to the straight line of y equals 2x plus 10 on the Cartesian plane?

The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5


What is the perpendicular distance from the point 3 -4 on the Cartesian plane to the line 5x -2y equals 3 rounding off work to three decimal places?

Equation: 5x-2y = 3 Perpendicular equation: 2x+5y = -14 Both equations intersect at: (-13/29, -76/29) Perpendicular distance to 3 decimal places: 3.714


What is always perpendicular to -3x plus y equals 2?

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What equation represents a line perpendicular to y equals x and passing through the points 0 0?

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The line given by the equation y equals -8x is perpendicular to what line?

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What is the equation of the line perpendicular to y equals 3x minus 7 that contains points 6 and 8?

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What is the equation of the line passing through 3 -4 and it is perpendicular to the line 5x -2y equals 3?

Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0


What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane?

Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula


What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?

Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula


What is the perpendicular from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane with work shown?

If you mean the perpendicular distance then it is worked out as follows:- Equation: y = 2x+10 Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 The two equations intersect at: (-2,6) Perpendicular distance is the square root of: (-2-2)2+(6-4)2 = 4.472 to 3 d.p.