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Y=2x+c where c is arbitery constant

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Q: What is the equation of a line which has gradient 2?
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Related questions

What is the gradient of a line with the equation y 3x - 2?

1


What is the equation for the line with coordinates 2 and 2?

There are an infinity of lines passing through the point whose coordinates are (2,2), each with a different slope [gradient]. The equation of the line will be of the form (y - 2) = m*(x - 2) where m is the gradient.


How do you find the gradient of a line with the equation y equals 3x plus 2?

An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3


What is the equation of the line with gradient 2 and y intercept of 3?

y = 2x + 3


What is the equation of the line with an x-intercept of -1 and a y-intercept of 2?

-3


What is the equation of a line perpendicular to 3x-2y7 with a y- intercept of 5?

The gradient of the given line is 2/3. Gradient of the perpendicular is -3/2 The equation, therefore, is y = -(3/2)x + 5 or 2y = -3x + 10 or 3x + 2y - 10 = 0


What does state the equation of the straight line with a gradient of 2 passing through the y axis at 0 4?

It is the equation of a straight line in the form of: y = 2x+4


How can you find equation of the line passing thruogh two points?

. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)


What is the gradient of a line with the equation y equals 5x - 2?

7


What is the slope of the line that has the equation y4x 2?

y = 4x + 2 It has a slope (gradient) or 4. The slope/gradient of a linear function is simply the number in front of the x when the equation is in the form y=mx+b. (the coefficient of x).


How do you find the equation of a line that has a gradient of 2 and passes through the point 3 and 2?

y=mx+cThe equation of the line is y = mx + c wherem is the gradient of the line and c is the y-interceptThat is, y = 2x + c where c is a constant to be determined.Since the point (3, 2) is on the line,2 = 6 + c so that c = -4So the line is y = 2x - 4


What equation represents a line perpendicular to the line whose equation is 2x plus 3y equals 12?

Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel