x2 + y2 = 16
x² + y² = 4.
It is x2 + y2 = 4
x2 + y2 = 2
a diameter
x2 + y2 = 4.
x² + y² = 4.
It is x2 + y2 = 4
x2 + y2 = 2
The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4
x2 + y2= 16
a diameter
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
x2 + y2 = 4.
x² + y² = 16.
Since the circle is centered at the origin, the equation of the circle is x2 + y2 = r2. So we have: x2 + y2 = (3/2)2 x2 + y2 = 9/4
If that equals 16 then the radius is 4
This makes no sence