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x2 + y2 = 16

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Q: What is the equation of the circle with the center at the origin and r 4?
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Related questions

What is the equation of a circle with a center at the origin and a radius of 2?

x² + y² = 4.


What is the equation of a circle whose center is at the origin and radius is 2?

It is x2 + y2 = 4


What is the equation of a circle whose center is at the origin and whose radius is 4?

x2 + y2 = 2


Find an equation of the circle that has center 0 2 and passes through the origin.?

The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4


This circle is centered at the origin and the length of its radius is 4 What is the equation of the circle?

x2 + y2= 16


What is a chord passing through the center of a circle?

a diameter


How do you graph the equation x squared plus y squared equals 16?

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)


What is the equation of the circle centred at the origin with a radius of 2?

x2 + y2 = 4.


What is the equation of a circle centered at the origin with a radius of 4?

x² + y² = 16.


This circle is centered at the origin and the length of its radius is 3 over 2 What is the equation of the circle?

Since the circle is centered at the origin, the equation of the circle is x2 + y2 = r2. So we have: x2 + y2 = (3/2)2 x2 + y2 = 9/4


The equation of a circle centered at the origin is x2 plus y2 16. What is the radius of the circle?

If that equals 16 then the radius is 4


What is the equation for a circle with a center of 3 and 1 and a radius of 4?

This makes no sence