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What is the equation whose solutions are x equals 13 over 11 and x equals 17 over 19?
Wiki User
∙ 10y ago
x = 13/11 & x = 17/19
Hence
x - 13/11 = 0 & x - 17/19 = 0
We now form a quadratic equation from these two linear equations.
(x - 13/11)(x - 17/19) = 0
Using FOIL multiply out.
F(First ; x X x = x^2
O(Outside) ; x X -17/19 = -17x/19
I(Inside ; -13/11 X x = -13x/11
L(Last ; -13/11 X -17/19 = (+)221/209
Hence the equation becomes
x^2 - (17/19 + 13/11)x + 221/209
Add the fraction in 'x'
x^2 - 434x/209 + 221/209 = 0
This is the quadratic eq'n. However, we can remove the denominator of '209' by multiplying through;-
209x^2 - 434x + 221 = 0
lenpollock
Wiki User
∙ 10y ago209x2 - 434x + 221 = 0
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