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Q: What is the factor to x squared minus 7x minus 18?

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(x2 + 7x - 18) = (x + 9)(x - 2)

(7x + 8)(7x - 9)

(x + 1)(x - 8)

x(x - 7)

49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2

It is: (2x+3)(3x-8) when factored

(x - 5)(x + 12)

(x-6)(x-1)

(4x - 3)(x - 1)

(x - 2)(2x - 3)

-((x + 8)(x - 1))

14x squared minus 7x to the 3rd power can be factored to 7x2(2-x).

7x + 8

I suppose that would be 14x2 - 7x3. Just take out the common factor, 7x2. Divide each term by this factor to find the other factor.

A factor is like this. Original :x^2 + 7x - 18 (( x squared plus six x minus 18) Factored: (x+9)(x-2) ((x plus nine times x minus two))

7x2 - 14x = 7x(x - 2)

7x2 -4x -5x2 +2x = 2x2 -2x

No

(7x - 10)(x + 1)

(x - 4)(3x + 5)

x2 + 7x - 56 cannot be factorised.

7(x + 3)(x - 3)

It is (7x+3)(x+9) when factored

14x2 - 39x - 35 = (7x + 5)(2x - 7)

14x2-7x2-16 7x2-16 (this can't be simplified any more)