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Answered 2015-10-24 06:18:29

T^4 - 81 = (T² + 9) (T² - 9) = (T² + 9)(T + 3)(T - 3)

Including complex numbers this can be further factorised into:

(T + 3i) (T - 3i) (T + 3) (T - 3)

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t^4 - 81 = (t^2)^2 - (3^2)^2 = (t^2 - 3^2)(t^2 + 3^2) = (t - 3)(t + 3)(t^2 + 9)


16t(t + 4) is the factorization Usually it's set = to 0 16t (t+4) =0 So, either 16t = 0 or t + 4 = 0 t = 0 or t = -4


(t - 3)(t + 3)(t2 + 9)


T to the fourth power is already fully simplified unless you have a value for "t."



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t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9) t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3) so the factors of t4-81 are :(t2+9)(t+3)(t-3) Hope this helps :-) I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)


Q-T- Hush - 1960 The Carnival Caper Carnival Chaos 1-81 was released on: USA: 1960


if you mean T-3t+2t+4 (T and t is different variables):T-3t+2t+4=T-t+4if you mean t-3t+2t+4:t-3t+2t+4=4


t - 4 = -8t = -8 + 4t = -4



9 = T+4Take 4 from both sides9(-4) = T(-4)5=T:)


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x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4


(t + 2)/3 + (t - 4)/6 (the common denominator 6) = [(t + 2)(2)]/(3)(2) + (t - 4)/6 = (2t + 4)/6 + (t - 4)/6 = (2t + 4 + t - 4)/6 = 3t/6 = t/2


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8000 lb = 4 t(US)8000 lb = 4 t(US)8000 lb = 4 t(US)8000 lb = 4 t(US)8000 lb = 4 t(US)8000 lb = 4 t(US)


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10 < or = to T/4 x4 x 4 cancels out just leaves T 40 < or = to T T < or = to 40



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