Math and Arithmetic

# What is the factorization of T power 4 - 81?

###### Wiki User

T^4 - 81 = (T² + 9) (T² - 9) = (T² + 9)(T + 3)(T - 3)

Including complex numbers this can be further factorised into:

(T + 3i) (T - 3i) (T + 3) (T - 3)

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## Related Questions

t^4 - 81 = (t^2)^2 - (3^2)^2 = (t^2 - 3^2)(t^2 + 3^2) = (t - 3)(t + 3)(t^2 + 9)

16t(t + 4) is the factorization Usually it's set = to 0 16t (t+4) =0 So, either 16t = 0 or t + 4 = 0 t = 0 or t = -4

T to the fourth power is already fully simplified unless you have a value for "t."

t with a small 4 to the top right of it

The prime factorization for 68 is: 2 x 2 x 17

t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9) t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3) so the factors of t4-81 are :(t2+9)(t+3)(t-3) Hope this helps :-) I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)

Q-T- Hush - 1960 The Carnival Caper Carnival Chaos 1-81 was released on: USA: 1960

if you mean T-3t+2t+4 (T and t is different variables):T-3t+2t+4=T-t+4if you mean t-3t+2t+4:t-3t+2t+4=4

Edwin T. Layton died on April 12, 1984 at the age of 81.

x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4

(t + 2)/3 + (t - 4)/6 (the common denominator 6) = [(t + 2)(2)]/(3)(2) + (t - 4)/6 = (2t + 4)/6 + (t - 4)/6 = (2t + 4 + t - 4)/6 = 3t/6 = t/2

Tom T. Hall is 81 years old (birthdate: May 25, 1936).

Edwin T. Layton died on April 12, 1984 at the age of 81.

The T-O- Show - 2009 Star 81 3-7 was released on: USA: 3 October 2011

643 dosen`t have a prime factorization because it`s already prime.

8000 lb = 4 t(US)8000 lb = 4 t(US)8000 lb = 4 t(US)8000 lb = 4 t(US)8000 lb = 4 t(US)8000 lb = 4 t(US)

T. W. Power has written: 'The price of an apple'

10 &lt; or = to T/4 x4 x 4 cancels out just leaves T 40 &lt; or = to T T &lt; or = to 40

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