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Adele O'Hara

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3y ago
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8y ago

T^4 - 81 = (T² + 9) (T² - 9) = (T² + 9)(T + 3)(T - 3)

Including complex numbers this can be further factorised into:

(T + 3i) (T - 3i) (T + 3) (T - 3)

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Q: What is the factorization of T power 4 - 81?
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What are the factors of t4 - 81?

t^4 - 81 = (t^2)^2 - (3^2)^2 = (t^2 - 3^2)(t^2 + 3^2) = (t - 3)(t + 3)(t^2 + 9)


What is 9 to the power of -2?

81.


H equals 16t2 plus 64t?

16t(t + 4) is the factorization Usually it's set = to 0 16t (t+4) =0 So, either 16t = 0 or t + 4 = 0 t = 0 or t = -4


How do you simplify t 4 power?

T to the fourth power is already fully simplified unless you have a value for "t."


What is 15sto the 6 power t to the 4 power plus 95s to 5 power t to the 3 power plus 35 s to the 4 power t to the 5 power minus 35 s to the 2 power t divided by 5 s to the 2 power t?

You can take a 5s2t out of all of that, leaving yourself with 3s4t3 + 19s3t2 + 7s2t4 - 7


What is t to the fourth power?

t with a small 4 to the top right of it


How do you simplify t-4 power?

1


T is the prime factorization for 68?

The prime factorization for 68 is: 2 x 2 x 17


What is the factors of t4-81?

(t - 3)(t + 3)(t2 + 9)


What are the factorsof 81?

t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9) t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3) so the factors of t4-81 are :(t2+9)(t+3)(t-3) Hope this helps :-) I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)


When did Edwin T. Layton die?

Irving Layton died on January 4, 2006 at the age of 93.


In each what list terms that continue a possible pattern 1 16 81 256 625 Is it a arithmethic geometric or neither sequences?

Neither, it is a power sequence. t(n) = n4 so t(6) would be 64 = 1296