28 t2 - 17 t - 3 = (7t + 1) x (4t - 3)
(x+4)(x-7)
45 - 28 = 17.
45 - 17 = 28
x = -28 / -11^2
17 is a prime number. It is only evenly divisible by itself and one.The factors of 28 are: 1, 2, 4, 7, 14, and 28.The prime factors of 28 are: 2 and 7.
3x squared minus 25x minus 28
The square root of 28 minus the squared root of 7 =±2.64575131
(x+4)(x-7)
45 - 28 = 17.
45 - 17 = 28
x = -28 / -11^2
The answer is -68 (or negative sixty eight).
#
17 is a prime number. It is only evenly divisible by itself and one.The factors of 28 are: 1, 2, 4, 7, 14, and 28.The prime factors of 28 are: 2 and 7.
First you must square the 6 which the answer is 36. Then you subtract 36 from 8 and the answer is negative 28. Finally you solve negative 28 minus 28 (-28-28) which equals negative 56 (-56).
3 + 52 / 33 - 23 = 28/4 = 7
Integers are whole numbers as for example 28 minus 17 = 11