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Q: What is the first 3 terms in the sequence?

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2

The first four terms are 3 9 27 81 and 729 is the 6th term.

91=3n

10

a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....

0,1,1,2,3,5,8,13

a, ar, ar^2 and ar^3 where a and r are constants.

2,1,0 is th sequence of its terms

The sum of the terms in a sequence is called a series. Sequence is a function whose domain is the natural numbers. So f(1)= first entry in the sequence, and f(2) is the next.... f(n) is the nth term. We usually don't write sequences that way. Instead of f(1) we write, a1 to refer to the first term. The function tells us the rule we use to find the terms of the sequence. So for example, f says take n and square it. Then the first 3 terms of the sequence are 1, 4 and 9 and the first 3 terms of the series are 1, 5 and 14

4,8,12,16,20

10

the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4

5

three

29

nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.

5

5

-1 -3

n = 1 ---> 3 * 1 + 3 = 6 n = 2 ---> 3 * 2 + 3 = 9 first 2 have difference of 3, so you can keep adding 3 to find more terms. 6, 9, 12, 15

To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.

123456

The terms are: 4, 8 and 16

Find the sum of the first 11 terms in the sequence 3 7 11

The terms of a sequence added together is the sum.