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They are: 6 15 24 33 and 42
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The nth term for nĀ²-1?
5 first terms in n²+3
What is the first 5 terms of the sequence with nth term 6n-1?
5, 11, 17, 23, 29
What is the first 5 terms in a sequence when given the nth term n 7?
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
What is the nth term of 12 19 26 33 40?
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
The pattern of 5 12 19 26?
Expressed in terms of n, the nth term is equal to 7n - 2.
The nth term for nĀ²-1?
5 first terms in n²+3
What is the first 5 terms of the sequence with nth term 6n-1?
5, 11, 17, 23, 29
What is the first 5 terms in a sequence when given the nth term n 7?
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
What are the first 5 terms in the sequence whose nth term is given by 30-2n?
32, 60, 88, 116, 144
What is the sum of first six terms of a sequence whose nth term is 8 - n?
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
What are the first five terms of the sequence whose nth term is give 3n plus 2?
5, 8, 11, 14 and 17.
What is the nth term of 12 19 26 33 40?
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
What are the first 5 terms in the sequence whose nth term is given by 5n 2?
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
The pattern of 5 12 19 26?
Expressed in terms of n, the nth term is equal to 7n - 2.
How do you find the nth term of a pattern?
First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.
The sum of the first 5 terms of an arithmetic series is 85. The sum of the first 6 terms is 123. Determine the first four terms of the series.?
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
What is the nth term of 3 1 -1 -3 -5?
The nth term is: 5-2n
