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Q: What is the first six nonzero multiples of 5?

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They are the first three multiples of LCM(5, 9), that is, the first three multiples of 45.

5, 10, 15, 20, 25, 30

The first six multiples of 3 are 3, 6, 9, 12, 15, and 18. They are the products of 3 and the nonzero integers 1, 2, 3, 4, 5, and 6.

5 15 25 35

The product is 5x10x15x20x25 = 375000

The answer would be 750,000.

What are the first six multiples in 7

5, 10, 15, 20, 25, 30.

9x1= 9 9x2= 18 9x3= 27 9x4= 36 9x5= 45 9x6= 54 Is this what you mean?

5, 10, 15, 20, 25, 30, 35, 40.

The first 6 multiples of 5 are: 5, 10, 15, 20, 25, and 30.

30

The first five multiples of 10 are 10,20,30,40,50.... 1 * 10 = 10 2 * 10 = 20 3 * 10 = 30 4 * 10 = 40 5 * 10 = 50

1, 2, 3, 4, 5, 6, 7, 8, 9, 10

The first 6 multiples of 1 are: 1, 2, 3, 4, 5, and 6.

The first 5 multiples of 6 are: 6, 12, 18, 24, and 30.The first 5 multiples of 9 are: 9, 18, 27, 36, and 45.

Assuming positive multiples, 5, 10, 15, 20, 25, 30

It is a sentence which makes no sense.

They are 5, 10, 15, 20, 25 and 30.

We can't answer that without knowing the numbers. The first six multiples of 5 are 5, 10, 15, 20, 25, 30

They are: 5 10 15 20 25 and 30

To get the multiples, just calculate: 6 x 1 6 x 2 etc.

6 8 9 2 5 7

Well 5x6 has only one answer: 30 But respectably the first five multiples of five are 5,10,15,20 and 25 And the first five of six are 6,12,18,24 and thirty

The first 5 multiples of 5 are: 5, 10, 15, 20, 25 The first 5 multiples of 9 are: 9, 18, 27, 36, 45 The first 5 multiples of both 5 and 9 are: 45, 90, 135, 180, 225