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The gravetational force on an object is described with the formula: F = g * m

With g = 9.81 and a mass of 0.08 m3 * 7840 kg/m3 = 627.2 kg

627.2 * 9.81 = 6153 Newton.

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Q: What is the force of gravity acting on a block in water if the block has a volume of 0.08 m and a density of 7840 kg m?
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A steel block has a volume of 0.08 m and a density of 7840 kgm What is the force of gravity acting on the block the weight in water?

5362.56 NEWTONS


A steel block has a volume of 008m and a density of 7840 kgm what is the force of gravity acting on the block in water?

9.81 m/s2 nine and eighty-one hundredths meters per second squared.


A steel block has a volme of 0.08m3 and a density of 7840 kgm3 what is the force of gravity acting on the block?

Let us formulate the formula. If suppose m is the mass of the body then mg will be the force acting on it due to gravity. If d is the density and v the volume then v d will be the mass. Hence the force due to gravity will become v d g. This force acting due to gravity is other wise known as weight of the body. Now in your problem note down the unit. It has to be in SI system. Unit for volume is m3 and that for density is kg m-3. The unit for g is m/s2 Hence as per your problem, simply multiply 0.08, 7840 and 9.8. You will get the required answer.


A steel block has a volume of 0.08m3 and a density of 7840kgm3 what is the force of gravity acting on the block in water?

Density = 7,840 kg/m3 Volume = 0.008 m3 (= 8 liters). Mass = (7,840 x 0.008) = 62.72 kg Force of gravity on the block = (9.8 x 62.72) = 614.656 newtons (138.27 pounds) Bouyant force = weight of 8 liters of water = 78.4 newtons (17.64 pounds) Weight of the block in water = (614.656 - 78.4) = 536.256 newtons (120.64 pounds)


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