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Q: What is the formula for the nth term of this sequence 14 22 30 38 46?

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This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.

The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)

They are: nth term = 6n-4 and the 14th term is 80

Clearly here the nth term isn't n25.

The nth term is: 3n+2 and so the next number will be 20

The nth term in this sequence is 4n - 2.

If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.

t(n) = (-5n4 + 62n3 - 247n2 + 334n - 36)/6

t(n) = 10 - 6n where n = 1, 2, 3, ...

5, 8, 11, 14 and 17.

It is: nth term = -4n+14

It is: nth term = 6n-4

First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.

The nth term is 2 + 3n.

You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4

Given ANY number at all, it is possible to find a cubic polynomial such that that particular number is the nth number in a sequence starting with the above three. The simplest rule, however, is Un = 5n + 9

The nth term of this sequence is 3n + 4

The differnace between the numbr is 7, therefore the first part of the formula will be 7n, now for the first term we replace n with one so nx7=7 and to get to 10 you need to add 3 making the nth term 7n+3, To check your answer you must replace n with the two (for the second term) which comes to 14 to get to seventeen you need to add three so the formula nth term 7n+3, hope this helped

To find out the equation for a sequence, the first thing you note is the difference between the numbers. In this case the difference is: -8, -8, -8, -8 Thus the formula will be x-8n where x is not yet known. For linear sequences like the one above, x is the 0th term. In this case it would be the term that would come before 22, or 22+8, or 30. Thus the equation for the nth term is 30-8n

the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps

14+9n

The differences are 3, 5, 7, 9,11, ... and the first term is -1; the nth term is: n² - 2

The nth term is 3n+2 and so the next number will be 17

42

There are infinitely many formulae that generate that sequence for the first 5 terms, but then give different terms for the 6th and onwards. However, the simplest formula (and the one that I guess your teacher is expecting) is based on the fact that there is a fixed common difference of 6 between terms, giving t(n) = 6n - 4 for n = 1, 2, 3, ...

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