Oxygen is a non meta element. Atomic mass of it is 16.
The formula of an oxygen molecule is O2 (2 is a subscript but now WA doesn't permit to write a subscript).15.9994 g/mol is the molecular mass of oxygen. Formula mass is a sum of atomic mass of atoms in the molecule. In O2 there are two oxygen so it will be about 32g/mol
The formula weight for O3 is the same as the molecular weight which is taking all the elements, multiplying its mass, and then adding the products. Oxygen's mass is 16 g on the periodic table & there's three of them so: 16x3= 48 g (molecular weight) = This is your Formula weight. Hope that helped.
Since the atomic mass of sulfur is very close to twice the atomic mass of oxygen, the ratio of numbers of oxygen atoms to numbers of oxygen atoms is close to 43:28.5. The closest ratio of small integers is 3:2; therefore the empirical formula is S2O3.
640 grams of Oxygen
Relative atomic mass: Zinc= 65 Nitrogen= 14 Oxygen= 16 Nitrate= nitrogen and oxygen= 30 Formula for zinc nitrate: Zn(NO3)2 NO= 30 NO3= 90 Zn= 65 Zn(NO3) x2 = Zn(NO3)2= 310 Formula mass (molecular mass)(Mr) of zinc nitrate = 310
Well, the formula for zircon is ZrSiO4 so, this means that you need to find the molar mass of the entire thing. Once you have this you find the percent mass that oxygen takes, by dividing the mass of the oxygen by the mass of the total compound. Then you multiply this number by the 10g and voila.
Tin sulfate is made out of the elements tin, sulfur and oxygen. The mass numbers of tin, oxygen and sulfur are 117, 16 and 32 respectively. Therefore the molecular weight of the empirical formula is 215 g/mol.
because of the polarity of the oxygen-hydrogen bond
This mass is 244,459.10e23 g.
The relative atomic mass of hydrogen is 1 and for oxygen it's 16. This gives water (which has the formula H2O) a molecular mass of 18.
The formula shows that oxygen is one atom out three in the formula unit, so that the atomic percent of oxygen in the compound is 33.333.......... By adding the gram atomic masses of the three elements, one obtains 23.95 as the gram formula mass, to the justified number of significant digits (the four digits in the value for the gram atomic mass of lithium), and 100 (15.9994/23.95) is 66.80 percent by mass of oxygen in LiOH.