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Well, you see, in this set of numbers it is very easy to tell that each number gets doubled

Q: What is the formula that represents this sequence 1 2 4 8 16 32 64 128?

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previous + 8

8/128 = 1/16 = 0.06258/128 = 1/16 = 0.06258/128 = 1/16 = 0.06258/128 = 1/16 = 0.0625

11000000 = 128+64=192 10101000 = 128+32+8=168 10101100 = 128+32+8+4=172 11110001 = 128+64+32+16+1=241

16% of 800 = 128

Un = 29 - 9n

Related questions

This sequence is called the doubling sequence.

8

The nth term in the sequence means an unspecified number an unspecified distance along the series. 8 16 32 64 128... n. It is also a shothand notation so the reader knows that the sequence continues.

256

24. It should be 32 which is double of 16

There are several versions, but this one works well enough. f(x)=2x (y equals two to the x power.)

512 / 2 = 256 256 / 2 = 128 128 / 2 = 64 64 / 2 = 32 32 / 2 = 16 16 / 2 = 8 8 / 2 = 4 4 / 2 = 2 2 / 2 = 1

previous + 8

128. 1+1=2 2+2=4 4+4= 16 16+16= 32 32+32= 64 64+64 = 128 128+128 = 256 256+256 =512 512+512= 1024 Each time take the answer from the previous problem and double it to find the next number in the sequence.

8/128 = 1/16 = 0.06258/128 = 1/16 = 0.06258/128 = 1/16 = 0.06258/128 = 1/16 = 0.0625

11000000 = 128+64=192 10101000 = 128+32+8=168 10101100 = 128+32+8+4=172 11110001 = 128+64+32+16+1=241

-4 +8 -16 +32 -64 +128 Next number in this sequence is 184