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Depending on which two angles you are talking about (all angles are given if it is a right triangle with 2 other angles given) you can use simple Trig functions to find the hypotenuse.

For instance, you have a triangle with sides a, b, c.

a=3

b=4

c=hypotenuse

You can have either one given and the other one a mystery it does not matter. What does matter is which angle is given. Probably one other than the 90 degree angle in all right triangles.

For this instance pretend we didn't have (b) and we only have (a).

In between the angle(a,c) we have approx. 37 degrees.

If you input that into the reciprocal of sin you will get 1/(sin37) = csc37 = 1.661 or approx 1.666 repeating.

Multiply that number by your (a) since csc (cosecant) is your hypotenuse (c) divided by your other length included with the angle (a). Doing so will seclude the hypotenuse to one side of the equation, therefore giving you the answer.

If you multiply 1.666 by three you get 5, which is what you get if you take the root of 32 + 42.

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Q: What is the formula to find hypotenuse of a right triangle with 2 angles given?
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