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Q: What is the four-digit no in which the first digit is one- third the second the third is the sum of the first and second and the last is three times the second?

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1349

4284

Look for the first digit that is different. In this case, the first digit after the decimal point. The number that has the larger digit in this position, is larger. If the first digit is the same, compare the second digit with the second digit, the third digit with the third digit, and so forth, until you find a difference.

182

The first and last, and the second and third.

263

Write them as decimals, and compare. If the first digit of two numbers is equal, compare the second digit; if the second digit is equal, compare the third digit, etc.

1155

1349

The first digit has 4 choices for its digit. The second digit has 6 choices and the third has 3. The solution would simply be 4*6*3=72 three digit numbers.

1

The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5

100000000*first digit+10000000*second digit+1000000*third digit+100000*fourth digit+10000*fifth digit+1000*sixth digit+100*seventh digit+10*eightth digit+1*nineth digit

-900

There are the digits 1 through 9 for the first digit. Then, we have 0 through 9 for the second digit - excluding the first digit. For the third digit, we have 0 through 9 excluding the two previous digits

2.3

There are 90 palindromes with 4 digits.The first digit can be any digit from the set {1,2,3,4,5,6,7,8,9}.With each choice of the first digit, the second can be any digit from the set {0,1,2,3,4,5,6,7,8,9}.That makes 9*10 = 90 permutations for the first two digits. These determine the palindrome since the third and fourth digits are the same as the second and first, respectively.

As your question is written, there are 720 possibilities, 10 x 9 x 8. There are 10 possibilities for the first digit. The second digit cannot be the same as the first, so that leaves 9 possibilities. The third digit cannot be the same as the first or second, so that leaves 8 possibilities.

27since there are 3 choices for the first digit and then 3 for the second and 3 for the third which is 3x3x3=27

No. Since the first digit (the "2" after the decimal point) is the same, you need to compare the second digit. You can fill out zeros after "0.2", writing it as "0.200". If the second digit is also the same, you can compare the third digit.

From left to right, choose the smallest digit for each position. Thus, the first digit would be 1, the second digit 0, the third digit 2, etc.

Let the first and third digits be equal. Choose any other number as the second digit. 202, 919, etc.

It is 56.90 - the first digit after the decimal point is tenths, the second hundredths and the third is thousandths.

In any two-digit multiplication sum, for example, 3 x 2 = 6, the first digit is called the multiplier, the second digit is called a multiplicand, and the third digit, the answer, is the product.

You multiply the first digit from the right by 1, the second digit from the right by 16, the third digit from the right by 16 squared, the fourth digit from the right by 16 cubed, etc., then add everything together.