Q: What is the full form of ace in a pack of card?

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1/13 (one thirteenth

The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.

Just a straight deal, the first card will be an ace 4 times out of 52, the second card will be an ace 3 times in 51. The total odds will be 12 times in 2652.However in the question posed the first card is an ace so the probability is 1 in 1, so the second card being an ace will occur 3 times in 51.In the question , the first card is ACE, and second is also an ACE. Hence probability is 1in 1.How ever the question should be framed "What is the probabilty for getting first card An ACE and also Second card as An ACE"

There is only one ace of hearts, but there is also an ace of clubs, an ace of diamonds and an ace of spades.

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In a normal pack there's only one of each card

There is nothing after a ace. It is the lowest card in the full deck.

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The probability of drawing an Ace from a 52 card deck is 4/52 or 1/13.

1/13 (one thirteenth

No, only the king, queen, and jack are face cards.

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Card decks have four suits - two black ones (spades and clubs) and two red ones (hearts and diamonds). Therefore, there are two red anythings in a deck.