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Q: What is the gcf of x2 and x6?

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The GCF is x2.

3,840. Pattern is x2, x4, x6, x8, x10, .....

x8

The GCF is 1.

(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)

Guessing they are powers and no operational symbol is between the two (ie a multiplication is assumed), then: x6 x2 = x6 + 2 = x8 Otherwise, re-ask with words for missing symbols, eg "what is x to the power 6 plus x to the power 2 simplified"

It is 36.

The GCF is x4

x6 + 3x4 - x2 - 3 = 0(x6 + 3x4) - (x2 + 3) = 0x4(x2 + 3) - (x2 + 3) = 0(x2 + 3)(x4 - 1) = 0(x2 + 3)[(x2)2 - 12] = 0(x2 + 3)(x2 + 1)(x2 - 1) = 0(x2 + 3)(x2 + 1)(x + 1)(x - 1) = 0x2 + 3 = 0 or x2 + 1 = 0 or x + 1 = 0 or x - 1 = 0x2 + 3 = 0x2 = -3x = ±√-3 = ±i√3 ≈ ±1.7ix2 + 1 = 0x2 = -1x = ±√-1 = ±i√1 ≈ ±ix + 1 = 0x = -1x - 1 = 0x = 1The solutions are x = ±1, ±i, ±1.7i.

The GCF is x2

(x1+x2+...+x5)/5 = 34 (x1+x2+...+x5)= 5 * 34 = 170 [(x1+x2+...+x5) + x6]/6 = 35 170 + x6 = 6*35 = 210 x6 =210-170=40 Answer is 40

The GCF is 1.

The infinite series is 1 - x2/2! + x4/4! - x6/6! + ...

do you mean (x2)(x2)(x)(x) would equal x6

X4 - 6X3 - 5x2X2(X2 - 6X - 5)X2======GCF

there are the power bricks x2 x4 x6 x8 x10!

x6 - 27 = (x2 - 3)*(x4 + 3x2 + 9) Danny rocks

No. The Asus M2A74 is only compatible with the Athlon II X2/X3/X4 and the Phenom II X2/X3/X4. However, the MSI 870-G45 is only $69.99 on Newegg.com, and is X6 CPU Certified. It's a good board, and would work perfectly with a Phenom II X6. If you're looking at motherboards, don't just look for a socket match for the Phenom II X6's, look for something in the specifications or on the box that SPECIFICALLY SAYS "X6 CPU Certified" or something similar.

There are infinite varieties of dimensions as 4'x6' , 3'x8', 12'x2', ..., etc

The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7

x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.

-x2(5x5 + 13)

cos(x) = 1 - x2/2! + x4/4! - x6/6! + ... where x is the angle measured in radians.

Cos(x) = 1 - x2/2! + x4/4! - x6/6! + ... where x is measured in radians

If we just assume that the contestant risks exactly how much the clue is originally worth on the Daily Doubles and they risk all their winning and get the clue correct in Final Jeopardy, here is the addition problem (In Dollars):'Single' Jeopardy:(200+400+600+800+1000)x6Double Jeopardy:(400+800+1200+1600+2000)x6Final Jeopardy:All that x2[(200+400+600+800+1000)x6]+[(400+800+1200+1600+2000)x6]x2=[(3000x6)+(6000x6)]x2=(18000+36000)x2=54000x2=$108,000.00