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Lorenza Kassulke
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∙ 11y ago3
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What is the equation of a line perpendicular to 3x-2y7 with a y- intercept of 5?
The gradient of the given line is 2/3. Gradient of the perpendicular is -3/2 The equation, therefore, is y = -(3/2)x + 5 or 2y = -3x + 10 or 3x + 2y - 10 = 0
What is the slope of 3 and y intercept -2?
It is a straight line equation in the form of: y = 3x-2
Parallel line to y equals 3x-2?
5
How do you answer the equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is?
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
Find the equation of the line in point slope form that passes through the point -4 7 and is parallel to the line represented by the equation 9x plus 3y 6?
If you mean: 9x+3y = 6 then y = -3x+2 and its parallel equation is y = -3x-5
What is the equation of a line perpendicular to 3x-2y7 with a y- intercept of 5?
The gradient of the given line is 2/3. Gradient of the perpendicular is -3/2 The equation, therefore, is y = -(3/2)x + 5 or 2y = -3x + 10 or 3x + 2y - 10 = 0
How do you find the gradient of a line with the equation y equals 3x plus 2?
An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3
What is the gradient of y equals 3x plus 2?
y=2 + 3x seems like a linear equation, therefore, y=3x + 2.The gradient is 3.
What is perpendicular to the line 3x plus y equals 2?
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
What is the gradient in the equation y equals 3x - 5?
-2
Which graph represents the equation y equals 3x plus 2?
The one which shows a straight line with a positive gradient of 3 and crossing the y axis at 2.
How do find the answer to the equation 3x plus 2y equals 36?
Well, you can't really solve for x or y because you only have one equation, but you could get the line of the straight line:3x + 2y = 362y = 36 - 3xy = 18 - 3x/2Where the gradient is -3/2 and the y interecept is 18.
What is the equation through the line passing points 0 4 and -2 -2 on a graph?
Gradient = (4 + 2)/(0 + 2) = 6/2 = 3 So the equation is (y + 2) = 3(x + 2) or y = 3x + 4
What is the equation joining the points of 2 4 and -3 1?
Gradient of line = (4 - 1)/(2 + 3) = 3/5 So general form of equation: y = 3x/5 + c where c is a constant or 5y = 3x + c' where c' = 5c is a constant The point (2,4) is on this line so 20 = 6 + c' so tha c' = 14 Therefore, the equation of the line is: 5y = 3x + 14
What is 3x plus 2y equals 8?
3x + 2y = 8 This is an equation. It could be the equation of a line.
Write the standard form equation of the line passing through 4 9 and perpendicular to 2x minus 3y equals 7?
With a line in the form y = mx + c, it has gradient m and the line perpendicular to it has gradient m' such that mm' = -1, ie m' = -1/m. A line through a point (x0, y0) with gradient m' has an equation of: y - y0 = m' (x - x0) which can be rearranged to a form for y = mx + c. Thus for the line 2x - 3y = 7: 2x - 3y = 7 → 3y = 2x + 7 → y = 2/3 x + 7/3 → it has gradient 2/3 → perpendicular line has gradient -3/2 → perpendicular line through (4, 9) perpendicular to 2x - 3y = 7 has equation: y - 9 = (-3/2)(x - 4) → 2y - 18 = -3(x - 4) → 2y - 18 = -3x + 12 → 2y = 30 - 3x → 3x + 2y = 30
What is the distance from the point 5 7 that is perpendicular to to the straight line equation of 3x-y plus 2 equals 0 on the Cartesian plane showing key aspects of work?
To find the perpendicular distance from a given point to a given line, find the equation of the line perpendicular to the given line which passes through the given point. Then the distance can be calculated as the distance from the given point to the point of intersection of the two lines, which can be calculated by using Pythagoras on the Cartesian coordinates of the two points. A line in the form y = mx + c has gradient m. If a line has gradient m, the line perpendicular to it has gradient m' such that mm' = -1, ie m' = -1/m (the negative reciprocal of the gradient). A line through a point (x0, y0) with gradient m has equation: y - yo = m(x - x0) Thus the equation of the line through (5, 7) that is perpendicular to 3x - y + 2 = 0 can be found. The intercept of this line with 3x - y + 2 = 0 can be calculated as there are now two simultaneous equations. → The perpendicular distance from (5, 7) to the line 3x - y + 2 = 0 is the distance form (5, 7) to this point of interception, calculated via Pythagoras: distance = √((change_in_x)^2 + (change_in_y)^2) This works out to be √10 ≈ 3.162
