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Q: What is the greatest common factor of 4a2 2a?
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Related questions

How would you factor 4a2 - 25?

(2a + 5)(2a - 5)


How do you factor 4a2 - 8a - 5?

(2a + 1)(2a - 5)


How would you factor 4a2 plus 25?

4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2


How do you factor 4a2 -4a - 120?

(2a + 10)(2a - 12)


What is the greatest common factor of 2a and 3a?

The greatest common factor (GCF) of 2a and 3a is a.


How do you factor 16a2-4b2?

4(4a2 - b2) 4(2a + b)(2a - b)


How do you simplify an expression in the format of 4a2 plus 4ab - y2 plus b2?

4a2 + 4ab - y2 + b2 You cannot simplify this expression because it does not contain like terms, but you can factor it such as: 4a2 + 4ab - y2 + b2 = (4a2 + 4ab + b2) - y2 = (2a + b)2 - y2 = [(2a + b) - y][(2a + b) + y]


How do you factorize 4a2-20ab2 plus 25b4?

4a2 - 20ab2 + 25b4 (2a - 5b2)(2a - 5b2) (2a - 5b2)2


What is the greatest common factor of 72a3b2 and 86a?

The GCF is 2a.


What is the greatest common factor of 2a and 4?

The GCF is 2.


How do you factor 8xA cubed plus C cubed?

(2a + c)(4a2 - 2ac + c2)


How do you prove the quadratic formula?

The essence of the proof is simply to complete the square for a generalised quadratic equation. Like this:ax2 + bx + c = 0Take 'a' outside:a[x2 + bx/a + c/a] = 0Divide through by 'a':x2 + bx/a + c/a = 0Complete the square:(x + b/2a)2 - b2/4a2 + c/a = 0Rearrange to find x:(x + b/2a)2 = b2/4a2 - c/ax + b/2a = (+/-)sqrt[b2/4a2 - c/a]x = -b/2a (+/-) sqrt[b2/4a2 - c/a]Finally, fiddle around so that (1/2a) can be taken out as a common factor:x = -b/2a (+/-) sqrt[b2/4a2 - 4ac/4a2]x = -b/2a (+/-) sqrt[(1/4a2)(b2 - 4ac)]x = -b/2a (+/-) sqrt(1/4a2)sqrt(b2 - 4ac)x = -b/2a (+/-) (1/2a)sqrt(b2 - 4ac)x = [ -b (+/-) sqrt(b2 - 4ac) ] / 2a.