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Q: If RS equals 3x plus 1 and ST equals 2x-2 and and RT equals 64 then find X?

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Related questions

2x2 equals 5

No.

2x2 + 3x - 20 = (x + 4)(2x - 5).

If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2

The discriminant is 1.

d/dx 2x2+3x+7=4x+3

2x2 + 3x + 1 = (x + 1)(2x + 1)

65

(2x - 1)(x - 1) so x = ½ or 1

factorises as (2x + 1)(x + 1) so x = -0.5 or -1

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x3 + 2x2 - 3x - 6 = (x2 - 3)(x + 2)

B- It is a many-to-one function

70000000y=35t

no

This expression could be reordered as 1 + 3x + 2x2.

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No. You'd have to use the ABC-formula

(2, -1)

Their graphs are.

(2x + 7)(x - 2)

(-2,-1)

If 2x2 + 3x + 9 = 0 then x = -0.75 - 1.984i or -0.75 + 1.984i where i is the imaginary square root of -1.

what is a slope

5