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What is the greatest possible area for a rectangle whose perimeter is 96 feet?
Wiki User
∙ 13y ago
The greatest possible area of a rectangle is simply the area of a square, which is a special type of rectangle.
in order to find the area of that square:
4s=96 (4s=4 sides)
s=24
A=lw
A=24*24
A=576
so the area of that rectangle would be 576 ft...
Wiki User
∙ 13y ago
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Greatest area is achieved by a square whose sides are 72/4 = 18 cm. The area, in that case, is 18*18 = 324 cm2
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56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
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The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
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What is the largest possible area for a rectangle with a perimeter of 72 cm?
Greatest area is achieved by a square whose sides are 72/4 = 18 cm. The area, in that case, is 18*18 = 324 cm2
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What is the perimeter of a rectangle whose length is 18 cm and breadth is 10 cm?
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