8 is the greatest possible whole number remainder, eg seventeen divided by nine...
When a number is divided by 32 what is the greatest value the remainder may have
The greatest possible remainder for 76 is to be divided by 2 leaving the result of 38. Thank you!
The remainder is always 31 or less.
14. The largest possible number for a remainder is 1 less than the divisor.
The largest possible remainder when dividing by any number N is N-1.
The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.
It is: 40
It is 22.
It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.
85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11
A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.
The answer is 1. The smallest prime is 2 and the greatest prime (of however many digits) must be odd. The remainder of ANY odd number when divided by 2 must be 1.
If you're dividing a whole number by 2, then the greatest possible remainder is 1.
The greatest possible remainder is 6. If it were 7 or more, you'd be able to take another 7 out of it.