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HCN + H20 => CN- + H3O+

0.45 X X

Solve for X

(4.0*10^-10) = x^2/0.45M

x=1.34e-5= [OH]

Find pOH= -log of the above number

then 14-4.87=pH= 9.13

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16y ago
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Q: What is the h3O concentration in 0.45 m hcn ka of hcn 4.0 10-10?
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