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What is the height of a rock that is thrown upward with an initial speed of 15 meter per second?
Wiki User
∙ 14y ago
We have no idea how big the rock is, and no way to figure it out. But we can calculate that
it reaches 11.48 meters above the ground before it starts falling.
Wiki User
∙ 14y ago
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If an object is thrown upward with an initial velocity of 32 feet per second from 40 feet above the ground write the height equation?
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
A ball is thrown upward at an initial velocity of 70 feet per second from the top of a 345 foot building -- How long before the ball hits the ground below?
By the Way, guys, this is based on the equation H= -16t2+vt+s
What object shoots upward with an initial velocity of 6 meters per second?
anything shot up with that initial velocity. There isn't anything in specific.
What is h equals -5t2 plus 40t?
That's the formula for the height of an object that was tossed upward at a speed of 40 meters per second, after ' t ' seconds . This object has to be something like a canonball, or a baseball pitched by a professional etc. The initial vertical speed of 40 meters per second is almost 90 miles per hour upward !
How fast is a stone moving when it reaches a height of 11 meters if it is vertically thrown upward with a speed of 18 meters per second?
v2 = u2 + 2as where v = current velocity, u = initial velocity, a = acceleration, and s = displacement. Taking a = - 9.8 ms-2 v2 = 182 - (9.8 x 11 x 2) = 108.4 v = 10.4 ms-1
How do you answer this physics question?
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
If an object is thrown upward with an initial velocity of 32 feet per second from 40 feet above the ground write the height equation?
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
How long will it take the ball to return to earth when it is thrown straight upward at 150' per second at the height of 5'?
OW! Not long enough!
How high can a ball go?
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
A stone is thrown straight upward and it rises to a height of 20 meters With what speed was it thrown?
6.261 m/s
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
What is tje velocity of a ball thrown upward at 16 ft/sec?
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
When will a stone return to the groun if it is thrown upward with an initial velocity of 16ms?
After just over three and a quarter seconds.
A ball thrown vertically upward has an initial potential energy of 100 J and an initial kinetic energy of 700 J At the top of the trajectory its energy in joules is?
100
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
velocity is found by dividing the distance with time. In a second the height traveled is found by multiplying the velocity by the time taken and then dividing the answer by two.
