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area_trapezoid =½ × sum_parallel_sides × perpendicular_height_between_them

→ height = 2 × area_trapezoid ÷ sum_parallel_sides

10 mm = 1 cm

→ height = 2 × 22.1778 cm² ÷ (66.6 ÷ 10 cm) = 6.66 cm

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βˆ™ 8y ago
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Q: What is the height of an isosceles trapezoid whose parallel sides add up to 66.6 mm and has an area of 22.1778 square cm showing work?
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