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area = ½ × sum_of_parallel_sides × perpendicular_distance_between_them

→ 234 sq units = ½ × (20 units + 32 units) × x

→ x × 26 units = 234 sq units

→ x = 234 sq units ÷ 26 units

→ x = 9 units

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Q: What is the height x of a trapezoid if its area is 234 square units and the two parallel sides are 20 and 32 units long?
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