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It is (6, 1).

Q: What is the image of (1-6) for a 270 counterclockwise rotation about the orgin?

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You went 360o in the same direction, so you end up with a circle.

The answer depends on the centre of rotation. Since this is not given, there can be no answer.

All rotations, other than those of 180 degrees should be further qualified as being clockwise or counter-clockwise. This one is not and I am assuming that the direction of rotation is the same as measurement of polar angles. Also, a rotation is not properly defined unless the centre of rotation is specified. I am assuming that the centre of rotation is the origin. Without these two assumptions any point in the plane can be the image. With the assumptions, for which there is no valid reason, the image is (3, -4).

270 degrees

3/4 of a rotation or 270 degrees

Related questions

It is (-6, -1).

Both will end up on the same place. Using a compass rose as an example: 270 clockwise will point to the west. 90 counterclockwise will also point west.

You went 360o in the same direction, so you end up with a circle.

The answer depends on the centre of rotation. Since this is not given, there can be no answer.

305

(-5,3)

(x,y)-->(y,-x) A transformation in which every point moves along a circular path around a fixed point

There are 270 degrees in 3/4 of a rotation

270 rule represent a 270 rotation to the left which is very easy

(x,y) to (x,-y). You would keep the x the same, but turn the y negative. This is actually the rule for a 90 degree counterclockwise rotation, but they're the same thing, they would go to the same coordinates.

Point A has coordinates (x,y). Point B (Point A rotated 270°) has coordinates (y,-x). Point C (horizontal image of Point B) has coordinates (-y,-x).

All rotations, other than those of 180 degrees should be further qualified as being clockwise or counter-clockwise. This one is not and I am assuming that the direction of rotation is the same as measurement of polar angles. Also, a rotation is not properly defined unless the centre of rotation is specified. I am assuming that the centre of rotation is the origin. Without these two assumptions any point in the plane can be the image. With the assumptions, for which there is no valid reason, the image is (3, -4).