Its (-4, 0) and (4, 2) not (40) and (42)
8x-5y = -40 -5y = -8x-40 y = 1.6x+8 which is now in slope intercept form
If you mean: 5x-2y = 40 then y = 2.5x-20 whereas -20 is the y intercept and 2.5 is the slope
First, put the equation in slope-intervcept form y=mx + b 5y=4x + 40 The y intercept is where x=0 so- 5y= 4(0) +40 solve for y y intercept = (0,8) For the x intercept, y=0 0=4x+40 -4x=40 x= -10 xintercept =( -10.0)
The equation for the line can be written in slope-intercept form as y = mx + b, where m is the slope and b is the y-intercept. Since we know that the slope is -45 and the point (1, -5) lies on the line, we can write the equation as y = -45x + b. To find b, substitute the x and y values of the point into the equation and solve for b: -5 = -45(1) + b. Simplifying the equation gives b = 40. Therefore, the equation for the line is y = -45x + 40.
Since the equation is written in the form y = mx + c, the slope is simply m. In this case, m = 2.
5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form
8x-5y = -40 -5y = -8x-40 y = 1.6x+8 which is now in slope intercept form
If you mean: 5x-2y = 40 then y = 2.5x-20 whereas -20 is the y intercept and 2.5 is the slope
If the equation is -20x-5y=40 then the answer is -5y=20x+40 which equals y=-4x-8 If the equation is -20x+5y=40 then the answer is 5y=20x+40 which equals y=4x+8
First, put the equation in slope-intervcept form y=mx + b 5y=4x + 40 The y intercept is where x=0 so- 5y= 4(0) +40 solve for y y intercept = (0,8) For the x intercept, y=0 0=4x+40 -4x=40 x= -10 xintercept =( -10.0)
If you mean: 4x+5y = 40 then y = -0.8x+8 whereas as -0.8 is the slope and 8 is the y intercept of a straight line equation
If you meant 4x=3y-120 ==> 4x +120 = 3y ==> 4/3x+40=y In y=4/3x+40 4/3 is the slope (y will be increased by 4 when x is increased of 3) and +40 is the y intercept (when x is zero y is +40)
The equation for the line can be written in slope-intercept form as y = mx + b, where m is the slope and b is the y-intercept. Since we know that the slope is -45 and the point (1, -5) lies on the line, we can write the equation as y = -45x + b. To find b, substitute the x and y values of the point into the equation and solve for b: -5 = -45(1) + b. Simplifying the equation gives b = 40. Therefore, the equation for the line is y = -45x + 40.
60
Since the equation is written in the form y = mx + c, the slope is simply m. In this case, m = 2.
Points: (40, -64) and (41, -35) Slope: 29
The browser used for posting question is rubbish. It rejects very many mathematical symbols and so the symbol before 480 is not visible to is. The best that I can do is say that the equation would be y = 2x +/- 30