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Given the limitations of this browser, I will use S to denote integral (the stretched S).

Int = S cos(x)*sin3(x) dx

Let t = sin(x) then dt = cos(x)dx

so Int = S t3dt = 1/4*t4 + c

Substituting back for x,

Int = sin4(x) / 4 + c

Given the limitations of this browser, I will use S to denote integral (the stretched S).

Int = S cos(x)*sin3(x) dx

Let t = sin(x) then dt = cos(x)dx

so Int = S t3dt = 1/4*t4 + c

Substituting back for x,

Int = sin4(x) / 4 + c

Given the limitations of this browser, I will use S to denote integral (the stretched S).

Int = S cos(x)*sin3(x) dx

Let t = sin(x) then dt = cos(x)dx

so Int = S t3dt = 1/4*t4 + c

Substituting back for x,

Int = sin4(x) / 4 + c

Given the limitations of this browser, I will use S to denote integral (the stretched S).

Int = S cos(x)*sin3(x) dx

Let t = sin(x) then dt = cos(x)dx

so Int = S t3dt = 1/4*t4 + c

Substituting back for x,

Int = sin4(x) / 4 + c

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11y ago
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Wiki User

11y ago

Given the limitations of this browser, I will use S to denote integral (the stretched S).

Int = S cos(x)*sin3(x) dx

Let t = sin(x) then dt = cos(x)dx

so Int = S t3dt = 1/4*t4 + c

Substituting back for x,

Int = sin4(x) / 4 + c

This answer is:
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