989
55
23
A digit is part of a number. the number 23 has two digits 2 and 3.
The answer depends on the context: whether it is a random 2-digit number, or a 2-digit number on a spin of a roulette wheel, or some other trial.
2 because it is
The largest 3 digit number which when divided by 69 and 12 to give a remainder of 1 is 829. What we want is one more than a common multiple of 69 and 12. The common multiples of 69 and 12 are the multiples of their least common multiple: 69 = 3 x 23 12 = 2^2 x 3 → lcm = 2^2 x 3 x 23 = 276 The largest multiple of 276 which is a 3 digit number: 999 ÷ 276 = 3 r 171 → largest 3 digit multiple of 276 is 3 × 276 = 828 → the required number is 828 + 1 = 829.
A multiple is a number that may be divided by another number with no remainder. Therefore, 90 is the largest two-digit multiple of 10, because 10x9 = 90, or 90 divided by 10 =9.
I think its 77 New author: No, 77 is a multiple of 7 and 11 too. So it is 23, see! And the word is digit not didget!
89+24 change one number to a multiple of ten 90 is closest to 89 and you added by one digit adjust the other number (drop the second number by the same digit as the first number adjusted (one digit). 23 90+23=113 89+24=113
55
23
23
yep e.g 18 and 17,,, 24 and 23...... :(
A digit is part of a number. the number 23 has two digits 2 and 3.
18
There are none but the smallest 3 digit number is 161
It is: 23 times 1 = 23 which is a prime number