If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3.
If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5.
Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15).
So what is needed is an even multiple of 15 less than or equal to 1000:
1000 ÷ 15 = 662/3
Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.
It is 997.
A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.
It is a factor of that number and leaves no remainder
85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11
It is a number which, when divided by 2, leaves no remainder.
It is any number which, when divided by 2, leaves no remainder.
14. The largest possible number for a remainder is 1 less than the divisor.
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
If it leaves no remainder when divided by 2 then it is an even number.
It is a number which leaves no remainder when divided by 2.
The largest possible remainder when dividing by any number N is N-1.
The largest 5 digit number is 99999. If this is divided by 11 it leaves a remainder of 9. Therefore the largest 5 digit number divisible by 11 is 99999 - 9 = 99990.
The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.
Do you mean what, when divided by 2, leaves a remainder? That'd be any odd number (or fraction).
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