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The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.

Q: What is the largest possible number for the remainder if a whole number is divided by 6?

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5

14, which is 15 minus 1.

9

That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.

The largest remainder would be 8, because if it were 9 you could divide the number once more. The largest remainder you can have is always one less than what you're dividing by. So if you're dividing by 10, your largest remainder is 9. If you're dividing by 100, it's 99. And so on.

Related questions

14. The largest possible number for a remainder is 1 less than the divisor.

The largest possible remainder when dividing by any number N is N-1.

5

2

The largest [integer] remainder is 10. If the remainder was any more you would get one (or more) lots of 11.

14, which is 15 minus 1.

The remainder is the number that is left over after the initial value has been divided as much as it can. If any numbers greater than 48 were present as a remainder, then these could be divided further into 48. If 48 is present as the remainder, then this can be divided by 48 to give 1, leaving no remainder. Thus, the largest possible remainder if the divisor is 48 is 47.

9

That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.

The largest remainder would be 8, because if it were 9 you could divide the number once more. The largest remainder you can have is always one less than what you're dividing by. So if you're dividing by 10, your largest remainder is 9. If you're dividing by 100, it's 99. And so on.

6

799