Oct 14, 2012 Thread starter #1 D dwsmith Well-known member Feb 1, 2012 1,673 Suppose that $f(\theta)$ is a continuous periodic piecewise differentiable function. Prove that $f(\theta) = f(0) + \int_0^{\theta}g(t)dt$ for a piecewise continuous $g$. I just need a nudge in the right direction here.

Suppose that $f(\theta)$ is a continuous periodic piecewise differentiable function. Prove that $f(\theta) = f(0) + \int_0^{\theta}g(t)dt$ for a piecewise continuous $g$. I just need a nudge in the right direction here.

Oct 20, 2012 #2 G girdav Member Feb 1, 2012 96 Can you do it when $f$ is differentiable? THen use the fact that there are only finite many points where $f$ is not differentiable.

Can you do it when $f$ is differentiable? THen use the fact that there are only finite many points where $f$ is not differentiable.