Four. (100 x 10 = 1,000)
If two numbers have m and n significant digits, respectively, then then product can have at most m+n. However, the normally it is the minimum of m and n.
Mutilply the values of the digits.
88
The answer will depend on the order in which you do partial products. It is quite common in the UK for the first partial product to be the two digits in the tens' place and so that is often the largest. This ties in with the method for multiplying two binomials when they move on to algebra.
Multiplying mixed decimals is almost just like multiplying whole numbers.For example:5.21 * 1.1You multiply these two numbers as if they didn't have decimal points, and you get 5,731; however, don't forget that you have decimals!Count the total number of digits after the decimal in each factor. You should get 3 since 5.21 has two digits after the decimal, and 1.1 has one digit after the decimal. 2 + 1 = 3Since you have 3 for that total, take the product (which is 5,731) and move the decimal point of that 3 spaces to the left.Your final product is 5.731:]
63
61 is prime. You cannot make 61 by multiplying four digits.
When multiplying by ten the digits shift to the left
If two decimal numbers have x and y digits after the decimal point respectively, then their product has (x + y) digits after the decimal point.
If two numbers have m and n significant digits, respectively, then then product can have at most m+n. However, the normally it is the minimum of m and n.
Because the number of digits after the decimal place in a product does not require that.
If the two multiplicands have X and Y digits after the decimal place then their product (before removing any trailing 0s) has (X+Y) digits after the decimal point.
44. Also works for 36, 63.
Yes.
Because when adding or subtracting, the operations must take account of the place values of individual digits in the numbers. When multiplying, only the overall order of magnitudes are relevant for placing the decimal point in the product.
Mutilply the values of the digits.
It should be obvious (it is, isn't it? am I expecting too much of today's educational system?) that the largest possible result of multiplying two two digit numbers is 99x99 = 9801, which has four digits, and the smallest possible result is 10x10 = 100, which has three digits.