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What is the least number which divides 285 and 1249 leaving remainders 9 and 7?
Wiki User
∙ 6y ago
To solve this you need the first common factor of 285 - 9 = 276 and 1249 - 7 = 1242 which is greater than 9 (if it was 9 or less it could NOT leave a remainder of 9 when divided into 285):
Common factors of 276 and 1242 are the factors of their hcf:
276 = 2² x 3 x 23
1242 = 2 x 3² x 23
hcf = 2 x 3 x 23 = 138
The factors of 138 which are the common factors of 276 and 1242 are: 1, 2, 3, 6, 23, 46, 69, 138
The first one greater than 9 is 23
→23 is the least number which divides 285 and 1249 to leave remainders of 9 and 7 respectively.
Wiki User
∙ 6y ago
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