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# What is the least number which divides 285 and 1249 leaving remainders 9 and 7?

Updated: 9/26/2023

Wiki User

6y ago

To solve this you need the first common factor of 285 - 9 = 276 and 1249 - 7 = 1242 which is greater than 9 (if it was 9 or less it could NOT leave a remainder of 9 when divided into 285):

Common factors of 276 and 1242 are the factors of their hcf:

276 = 2² x 3 x 23

1242 = 2 x 3² x 23

hcf = 2 x 3 x 23 = 138

The factors of 138 which are the common factors of 276 and 1242 are: 1, 2, 3, 6, 23, 46, 69, 138

The first one greater than 9 is 23

→23 is the least number which divides 285 and 1249 to leave remainders of 9 and 7 respectively.

Wiki User

6y ago

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Q: What is the least number which divides 285 and 1249 leaving remainders 9 and 7?
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