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What is the length and width of a rectangular lot if its perimeter is 88m and its area is 480m2?
Wiki User
∙ 12y ago
The equation for the perimeter is: 2(L + W) = 88m ie L + W = 44m
So that L = 44 - W
Then area = L*W = 480 m2
is equivalents to (44 - W)*W = 480
Or W2 - 44W + 480 = 0
which gives W = 20 or W = 24
if W = 20 then L = 24 and if W = 24 the L = 20
However, since conventionally, L>W, L = 24m, W = 20m
Wiki User
∙ 12y ago
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