11 ft.
11+11+6+6=34
width=5 length=12
2L + 2W = 34 L + W = 17 L = 2W - 4 3W - 4 = 17 3W = 21 W = 7 L = 10
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
The dimensions of the rectangle are 2 units and 15 units
Two ends make 8, so two sides must make 34 - 8 = 26, so each side is 13, which is the length.
width=5 length=12
The length is 14 cm
34 feet
12 meters
length = 34 and width = 3 Perimeter = 34+34+3+3 = 74 Area = 34*3 = 102
Width = 3 Length = 34
Its width would be 2cm. To find the missing dimension, divide the perimeter by two, then subtract the known variable.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
4cm by 13cm
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
Given: 2w + 2l = 34 l = w + 2 Then: 2w + 2(w + 2) = 34 4w = 30 w = 7.5 l = 9.5
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.