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Q: What is the length of a rectangle with the width at 17 and height at 12?

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The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.

Width is 5.

Area = 12 x 10 = 120 Sq feetAnswerArea = length x height. So, 10 x 12 = 120 square feet. AnswerWe know that the area of a rectangle is (length * width). Given: Length of the rectangle is 10 feet and the width is 12 feet.Therefore, the area of the rectangle = (10*12)The area of the rectangle is 120 square feet.12*10 = 120 square feet

The area of the rectangle is 72 square feet

Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.

156 feet is the area of a rectangle with a width of 12 feet and a height of 13 feet.

Width is 16.

width=5 length=12

-The height could be 6 and the width 2. -The height could be 1 and the width 12. -The height could be 3 and the width 4.

Area = Length * width A = 12 * 10 A = 120 units 2

Its height times width must equal 12. The rectangle could be: The height could be 1 and the width 12. The height could be 3 and the width 4. The height could be 6 and the width 2. But it could not have a height of 8 and width of 4 (since 8×4 = 32 square units of area).

The area of rectangle is : 120.0

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