The length of the rectangle is 27 meters and the width is 19 meters.
length = 22 meters and width = 6 meters
Length = 20 m and width = 9 m
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
length + width = 20/2 = 10 length = 7cm, width = 3cm
Width = 9 inches Length = 30 inches
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
Width: 16 meters Length: 21 meters Check: 16+21+16+21 = 74 meters which is its perimeter
length = 22 meters and width = 6 meters
Length + width = half of perimeter, so you need more information...
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
OK so we have two formulas: Length = width + 5 (since legth is 5 more than width) length + width + length + width = perimeter= 82 (form. for perm.) so we can replace every instance of "length" with "width + 5" since they are the same. width + 5 + width + width + 5 + width = 82 4xwidth + 10 = 82 4X width = 72 width = 23 so now go back and replace "width" with 23. length = 23 + 5 length = 28 There you go.
The picture has a perimeter of 22. If the width is 5 and the length is 6, which is in compliance with the parameters of the question, then 5+5+6+6=22.
The length is 15 feet.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
It works out as 19 m in length and 13 m in width.
width=5 length=12
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.