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What is the length of a triangle with an area of 18 square inches and a height of 12 inches?
Wiki User
∙ 7y ago
The length of a triangle with a height of 12 inches and an area of 18 square inches is 3 inches, since area is 1/2 * base * height. Therefore, 2 * area divided by height = 2 * 18 /12 = 3
Wiki User
∙ 7y ago
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A square and a triangle have equal areas and a side of the square is 10 inches and the base of the triangle is 10 inches then what is the height of the triangle?
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
How can you find the base of a right triangle when you have the height and hypotenuse?
The square of the length of the base plus the square of the length of the height will equal the square of the length of the hypotenuse of your right triangle, per Pythagoras. Square the hypotenuse, subtract the square of the height, and then find the positive square root of that and you'll have the base of your right triangle.
What is the area of a triangle with a base of 15 inches and height of 4inches?
30 square inches. Area of triangle = (base x height) divided by 2.
A rectangle and triangle have equal areas - the rectangle's length is 12 inches and its width is 8 inches so if the base of the triangle is 32 inches what is the length in inches of the altitude drawn?
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
If the triangle has a height of 14 inches and a base of 9 inches what is the area?
area of a triangle = .5 * base * height In this case .5 * 9 * 14 = 63 square inches
The height of a triangle is four times the length of the base find the base and height of the triangle if the base is 18 square inches?
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
How can you find the area of a triangle in square inches?
-- Measure the length of the base, in inches. -- Measure the height of the triangle, in inches. -- Multiply the two numbers and take 1/2 of the product. 1/2 of the product is the area of the triangle, in square inches.
Select all the triangles that would have an area of 18 square inches. Answer Choices A triangle with a base length of 9 in. and a height of 2 in. A triangle with a base length of 9 in. and a height of?
The first is clearly not a suitable triangle.
What is the area of a right triangle with a base length of six inches and a height of six inches?
18 square inches
A square and a triangle have equal areas and a side of the square is 10 inches and the base of the triangle is 10 inches then what is the height of the triangle?
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
How can you find the base of a right triangle when you have the height and hypotenuse?
The square of the length of the base plus the square of the length of the height will equal the square of the length of the hypotenuse of your right triangle, per Pythagoras. Square the hypotenuse, subtract the square of the height, and then find the positive square root of that and you'll have the base of your right triangle.
If a triangle has a height of 8 inches and an area of 120 sq inches what is the length of the base?
30 inches because 0.5*30*8 = 120 square inches
What is the area of a triangle with lenght of 16in and height of 14in?
If "length" means "length of side to which the height of 14 inches is perpendicular", area = (1/2)(14)(16) = 112 square inches. (These dimensionss of a triangle are more commonly called "base" and "altitude" respectively.)
What is the area of a triangle that is 12 in and 16 in?
What is 12 in ? And what is 16 in ? ? Are they the lengths of two sides of the triangle ? Are they the length of one side and the height of the triangle ? The area of any triangle is 1/2 of the product of (length of its base) x (its height).
If an obtuse triangle has a base that is 7 inches and height of 10 inches what is the area of the triangle?
35 square inches
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
How do you find out how many square meters are in a triangle?
The area of the triangle in square meters is (1/2 the length of the triangle's base, in meters) times (the length of the triangle's height, in meters).
