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If the sides of the triangle are 20 and 15 then by using Pythagoras' theorem the length of the hypotenuse works out as 25 units of measurement.

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Q: What is the length of ad if the hypotenuse of the right angles are ab 20 bc 15 and abd and abc?
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Right triangle ABC has two legs of equal length. How long is a leg if the hypotenuse has a length of 19?

Each leg is the square root of 180.5 which is about 13.435 rounded to 3 decimal places


Prove theorem the height of an isosceles triangle is the median?

The theorem is only true if the base is the side of different length.To see this consider the right angled isosceles triangle with sides 1, 1 and √2. If one of the sides of length 1 is the base, the height is obviously the other side of length 1, but it clearly does not meet the base at its mid-point to make it a median.So with an isosceles triangle ABC with sides AB & AC equal, angles ABC & ACB equal and side BC the base, we need to prove that the point X where the height (AX) meets BC is such that BX = CX.Consider triangles AXB and AXC.Angle AXB is a right angle, as is AXC (since AX is a height of triangle ABC).Side AB is the hypotenuse of triangle AXB; AC is the hypotenuse of triangle AXC; they are known to be equal (from isosceles triangle ABC)Side AX is common to both trianglesThus triangles AXB and AXC are congruent since we have a Right-angle, Hypotenuse, Side match.Thus XB must be the same length as XC, that is X is the mid-point of BC.As X is the mid-point of BC, AX is the median.


What is the length of BC in this triangle angle BAC equals 40 degrees and angle ABC equals 50 degrees and angle BCA equals 90 degrees .?

In order to find length BC the length of AC or length of the hypotenuse must be given


What type of triangle is angle abc obtuse acute or right?

If one of the angles is 90 degrees then it is right ange triangle If one of the angles is obtuse then it is an obtuse triangle If the three angles are 3 different acute then it is a scalene triangle If two of the angles are equal then it is an isosceles triangle If the three angles are equal then it is an equilateral triangle


Abc is a right angled triangle ac equals 6cm bc equals 9cm work out the length of ab give your answer to 3 sig figures?

If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)

Related questions

What is the length of the hypotenuse of the right triangle ABC round the answer to one decimal place?

7.2


What is the length of the hypotenuse of the rigth triangle ABC in if AC 6 and AD 5?

Assuming you mean side AB is 5: If angle B is the right angle, side AC is the hypotenuse and is of length 6. If angle A is the right angle, side BC is the hypotenuse and is of length sqrt(52 + 62) ~= 7.81 Angle C cannot be the right angle as then side AB would be the hypotenuse but the hypotenuse is the longest side and side AB is shorter than AC.


Right triangle ABC has two legs of equal length. How long is a leg if the hypotenuse has a length of 19?

Each leg is the square root of 180.5 which is about 13.435 rounded to 3 decimal places


What is the length of the ABC hypotenuse rounded to one decimal place?

You can make it whatever length you like by selecting the other sides appropriately.


What is the lenght of the hypotenuse of the right triangle ABC in if AC 6 and AD 5?

61


Do angles abc make a right angle?

Angle abc will form a right angle if and only if, segment ab is perpendicular to segment bc.


Segment ab equals 9 segment bc equals 12 what is the hypotenuse of right triangle abc?

15


Prove theorem the height of an isosceles triangle is the median?

The theorem is only true if the base is the side of different length.To see this consider the right angled isosceles triangle with sides 1, 1 and √2. If one of the sides of length 1 is the base, the height is obviously the other side of length 1, but it clearly does not meet the base at its mid-point to make it a median.So with an isosceles triangle ABC with sides AB & AC equal, angles ABC & ACB equal and side BC the base, we need to prove that the point X where the height (AX) meets BC is such that BX = CX.Consider triangles AXB and AXC.Angle AXB is a right angle, as is AXC (since AX is a height of triangle ABC).Side AB is the hypotenuse of triangle AXB; AC is the hypotenuse of triangle AXC; they are known to be equal (from isosceles triangle ABC)Side AX is common to both trianglesThus triangles AXB and AXC are congruent since we have a Right-angle, Hypotenuse, Side match.Thus XB must be the same length as XC, that is X is the mid-point of BC.As X is the mid-point of BC, AX is the median.


What is the length of BC in this triangle angle BAC equals 40 degrees and angle ABC equals 50 degrees and angle BCA equals 90 degrees .?

In order to find length BC the length of AC or length of the hypotenuse must be given


How do you figure out the angles if the hypotonuse is 128?

In a triangle ABC, when hypotenuse is 128 unit which is right angled at A. By phythagoras theorem H square = P square + B square root of hypotenuse = ROOT of 8square + root of 8square it means other two sides are equal therefore . assuming the sides equal to x we have 2x square=128 x square= 64 x = -+8 but length is always positive. therefore other two sides = x= 8


In a right angled triangle ABC the hypotenuse AC is equal to what?

In a right angled triangle its hypotenuse when squared is equal to the sum of its squared sides which is Pythagoras' theorem for a right angle triangle.


In a given triangle ABC - right-angled in B - with a fixed 2 meters hypotenuse - how to calculate the length of AB side for a variable C angle?

Use the definition of sine as opposite side divided by hypoteneuse. For this problem, the length of side AB equals 2 times the sine of angle C.