If the sides of the triangle are 20 and 15 then by using Pythagoras' theorem the length of the hypotenuse works out as 25 units of measurement.
Each leg is the square root of 180.5 which is about 13.435 rounded to 3 decimal places
The theorem is only true if the base is the side of different length.To see this consider the right angled isosceles triangle with sides 1, 1 and √2. If one of the sides of length 1 is the base, the height is obviously the other side of length 1, but it clearly does not meet the base at its mid-point to make it a median.So with an isosceles triangle ABC with sides AB & AC equal, angles ABC & ACB equal and side BC the base, we need to prove that the point X where the height (AX) meets BC is such that BX = CX.Consider triangles AXB and AXC.Angle AXB is a right angle, as is AXC (since AX is a height of triangle ABC).Side AB is the hypotenuse of triangle AXB; AC is the hypotenuse of triangle AXC; they are known to be equal (from isosceles triangle ABC)Side AX is common to both trianglesThus triangles AXB and AXC are congruent since we have a Right-angle, Hypotenuse, Side match.Thus XB must be the same length as XC, that is X is the mid-point of BC.As X is the mid-point of BC, AX is the median.
In order to find length BC the length of AC or length of the hypotenuse must be given
If one of the angles is 90 degrees then it is right ange triangle If one of the angles is obtuse then it is an obtuse triangle If the three angles are 3 different acute then it is a scalene triangle If two of the angles are equal then it is an isosceles triangle If the three angles are equal then it is an equilateral triangle
If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)
7.2
Assuming you mean side AB is 5: If angle B is the right angle, side AC is the hypotenuse and is of length 6. If angle A is the right angle, side BC is the hypotenuse and is of length sqrt(52 + 62) ~= 7.81 Angle C cannot be the right angle as then side AB would be the hypotenuse but the hypotenuse is the longest side and side AB is shorter than AC.
Each leg is the square root of 180.5 which is about 13.435 rounded to 3 decimal places
You can make it whatever length you like by selecting the other sides appropriately.
61
Angle abc will form a right angle if and only if, segment ab is perpendicular to segment bc.
15
The theorem is only true if the base is the side of different length.To see this consider the right angled isosceles triangle with sides 1, 1 and √2. If one of the sides of length 1 is the base, the height is obviously the other side of length 1, but it clearly does not meet the base at its mid-point to make it a median.So with an isosceles triangle ABC with sides AB & AC equal, angles ABC & ACB equal and side BC the base, we need to prove that the point X where the height (AX) meets BC is such that BX = CX.Consider triangles AXB and AXC.Angle AXB is a right angle, as is AXC (since AX is a height of triangle ABC).Side AB is the hypotenuse of triangle AXB; AC is the hypotenuse of triangle AXC; they are known to be equal (from isosceles triangle ABC)Side AX is common to both trianglesThus triangles AXB and AXC are congruent since we have a Right-angle, Hypotenuse, Side match.Thus XB must be the same length as XC, that is X is the mid-point of BC.As X is the mid-point of BC, AX is the median.
In order to find length BC the length of AC or length of the hypotenuse must be given
In a triangle ABC, when hypotenuse is 128 unit which is right angled at A. By phythagoras theorem H square = P square + B square root of hypotenuse = ROOT of 8square + root of 8square it means other two sides are equal therefore . assuming the sides equal to x we have 2x square=128 x square= 64 x = -+8 but length is always positive. therefore other two sides = x= 8
In a right angled triangle its hypotenuse when squared is equal to the sum of its squared sides which is Pythagoras' theorem for a right angle triangle.
Use the definition of sine as opposite side divided by hypoteneuse. For this problem, the length of side AB equals 2 times the sine of angle C.