The diagonal is 63.64 cm
If you are given the area of the square, then the length of each side is the square root of the area. If you are given the length of the diagonal of a square, then the lenght of each side is equal to the length of the diagonal divided by the square root of 2. l=sqrt(a) l=d/[sqrt(2)] l=length of side, d=diagonal, a=area, sqrt means square root
15.556 feet (rounded)
The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm
If the length of a side of the square is S units then the diagonal is S*sqrt(2) units in length.
Using Pythagoras' theorem each side will be 6.363961031 units in length.
If you are given the area of the square, then the length of each side is the square root of the area. If you are given the length of the diagonal of a square, then the lenght of each side is equal to the length of the diagonal divided by the square root of 2. l=sqrt(a) l=d/[sqrt(2)] l=length of side, d=diagonal, a=area, sqrt means square root
15.556 feet (rounded)
Divide the length of the diagonal of a square by 1.4142 (which is the square root of 2) to find the length of a side. Similarly, to find the length of the diagonal of a square, multiply the length of a side by 1.4142.
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
Each side is sqrt 72 ie 8.49 in
The diagonal length = 7.07 inches.
The side lengths of a square with a diagonal of 16 is: 11.31.
The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm
About 5.656854249 cm using Pythagoras' theorem: 2x2 = 64
A diagonal of a square measures: Side X sqrt(2).Approximately (8 cm) X (1.414) = 11.312 cm
If the length of a side of the square is S units then the diagonal is S*sqrt(2) units in length.
The diagonal is 21.21 decimeters.