Using Pythagoras' theorem it is 10 times the square root of 2 which is about 14 feet
14'
170
12.73 feet
18.9 feet
The diagonal of an 8 ft by 10 ft square, by Pythagoras, would be sqrt(82 + 102) = sqrt(64+100) = sqrt(164) = 12.806 ft (to 5 sig figs)
The edge length of a cube with a diagonal of 9 ft is: 5.196 feet.
18 ft Diagonal of a square is the square root of 2, times the side.
10 ft Because 102+102 = 200 and the square root of this is 10 times the square root of 2 which complies with Pythagoras' theorem.
The length of the diagonal is 208.7*sqrt(2) = 295.1 ft.
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
Diagonal = 18.867 feet.
3.5 ft
12.73 feet
18.9 feet
18.9 feet
Approximately 17 feet.
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
Two adjacent sides of a square and the diagonal joining their ends froms a right angle triangle. The legs of the triangle are 10 ft each and the diagonal is the hypotenuse. By pythagoras, diagonal = sqrt(102 + 102) = 10*sqrt(2) = 14.142 ft (to 3 dp).
5.7 ft