sqrt(ab^2 + bc^2)
Assuming you mean side AB is 5: If angle B is the right angle, side AC is the hypotenuse and is of length 6. If angle A is the right angle, side BC is the hypotenuse and is of length sqrt(52 + 62) ~= 7.81 Angle C cannot be the right angle as then side AB would be the hypotenuse but the hypotenuse is the longest side and side AB is shorter than AC.
The length of the hypotenuse is: 10
-- The length of each leg is (length of the hypotenuse) / sqrt(2) = 0.7071 x (hypotenuse). -- The length of the hypotenuse is (length of either leg) x sqrt(2) = 1.414 x (leg)
Take a right angled triangle ABC with the right angle at B, so that AC is the hypotenuse. Let AC be 1 unit long. Using the angle CAB, the length of AC and the trigonometric ratios: sin = opposite/hypotenuse ⇒ sin CAB = AB/AC = AB/1 = AB cos = adjacent/hypotenuse ⇒ cos CAB = BC/AC = BC/1 = BC Using Pythagoras: AB2 + BC2 = AC2 ⇒ (sin CAB)2 + (cos CAB)2 = 12 ⇒ sin2θ + cos2θ = 1
The hypotenuse of the nth triangle has a length of sqrt(n+1)
The length of the hypotenuse of a right triangle if AC equals 6 and AD equals 5 is: 7.81
Assuming you mean side AB is 5: If angle B is the right angle, side AC is the hypotenuse and is of length 6. If angle A is the right angle, side BC is the hypotenuse and is of length sqrt(52 + 62) ~= 7.81 Angle C cannot be the right angle as then side AB would be the hypotenuse but the hypotenuse is the longest side and side AB is shorter than AC.
The length is sqrt(61) units.
Let AB = 3 BC = 4 AC = ? AC2 = AB2 + BC2 AC2 = 32 + 42 AC2 = 25 AC = 5
The median to the hypotenuse of a right triangle that is 12 inches in length is 6 inches.
the length of the hypotenuse is 10.63
The length of the hypotenuse is a²+b ²=c ² assuming that a and b are the other 2 sides.
The length of the hypotenuse is: 10
Using Pythagoras' theorem the length of the hypotenuse is 13 units
The length of the hypotenuse is equal to the root of the sum of the squares of the other two sides.
Hypotenuse = 24
The hypotenuse is 30.