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Q: What is the length of the shorter leg of a right triangle if the longer leg has a length of 45 and the hypotenuse has a length of 53?

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The length of the longer leg of a right triangle is 3ftmore than three times the length of the shorter leg. The length of the hypotenuse is 4ftmore than three times the length of the shorter leg. Find the side lengths of the triangle.

If you have the shorter legs length, then for the hypotenuse, just multiply the shorter leg by 2. For the longer leg, multiply the shorter leg by the square root of 3.

If it is a 45-45-90 triangle, then divide the hypotenuse by the square root of 2. If it is a 30-60-90 triangle, then the shorter leg would be the hypotenuse divided by 2. And the longer leg would be the the shorter leg multiplied by the square root of 3.

The shorter leg is 9 feet long

The shorter leg is 6 feet long

23

There are an infinite number of different sets of lengths that will do it. You have to start by choosing the length of one side, and when you do that, here's how to find the others: Shorter leg = (longer leg) x 0.364 Shorter leg = (hypotenuse) x 0.342 Longer leg = (shorter leg) x 2.747 Longer leg = (hypotenuse) x 0.94 Hypotenuse = (shorter leg) / 0.342 Hypotenuse = (longer leg) / 0.94

The shorter leg is 1/2 of the hypotenuse, while the longer leg is (sin60°) times the hypotenuse or about 0.866 times as long. (7.8/0.866) gives the hypotenuse as 9.0 and 9.0/2 = about 4.5 unitsor use the tangent ratio:7.8/tan 60° = 4.5033321 or about 4.5 in length

Short leg is 6 feet.

Use the rule that the shortest leg has length p, the other leg has length 2p and the hypotenuse has length p*sqrt(3) Where sqrt(number) if the square root of the number.

.The hypotenuse is twice as long as the shorter leg The longer leg is twice as long as the shorter leg.

7.44 - 7.45

2.3

You need to know something else to solve: either the long leg or the angle edit: if it is a right triangle you can use a theorem to figure out the other sides. the smallest side is a, the hypotenuse is 2a, the longer leg is a * sqrt (3) if the hypotenuse is 20, the smaller leg is 10.

In a 30Â° 60Â° 90Â° triangle, the ratio (long leg)/hypotenuse = sqrt(3)/2 ~ 0.866The ratio (short leg)/hypotenuse = 1/2 = 0.5

The hypotenuse of any right triangle is longer than either one of the other two sides of the same right triangle. But it's shorter than their sum.

Starting with an equilateral triangle of side 2, dropping a perpendicular from one vertex to the opposite base creates two equal right angled triangles with hypotenuse of length 2, base length 1 and height of length √(22 - 12) = √3 which is the longer leg of the 30-60-90 triangle. Thus the ratio of longer_leg : hypotenuse is √3 : 2

To solve a 30-60-90 triangle, you need to know the length of one side. The hypotenuse is twice as long as the shortest leg (the side opposite the 30 angle) The longer leg (opposite the 60 angle) is the length of the shorter leg times the square root of 3. So in summary: If you know the hypotenuse, divide it by 2 to find the shorter leg, and multiply that times the square root of 3 to find the longer leg. If you know the longer leg, divide it by the square root of 3 to find the shorter leg, then multiply that by 2 to find the hypotenuse. If you know the shorter leg, multiply it by 2 to find the hypotenuse. Multiply the shorter leg length by the square root of 3 to find the longer leg.

1/2 sqrt(3) = 0.866 (rounded)

2 Square Root 3 And 4

Let's call the unknown length x and use Pythagoras' theorem: x2+(x+3)2 = (x+6)2 By substituting 9 for x you'll find that only 9 will satisfy the above conditions. Shorter side = 9 units Longer side = 12 units Hypotenuse = 15 units

The short side will be opposite the 30 degree angle. The longer leg is 10*sqrt(3) = 17.32 and the hypotenuse is 20.

No.

If the hypotenuse is 25 cm Then the shorter leg is 7 cm Using Pythagoras' theorem: (17+7)2+72 = 625 and its square root is 25 cm

9,3,6 The dimensions given above would not be suitable for a right angled triangle which presumably the question is asking about. The dimensions suitable for a right angled triangle in the question are: 9, 12, 15.