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What is the limit of x- sin x cos x over tan x -x as x tends to zero?
Duaa7
It is minus 1
I did this: sinx/cos x = tan x
sinx x = cosx tanx
you have
(x - sinxcosx) / (tanx -x)
(x- cos^2 x tan x)/(tanx -x)
let x =0
-cos^2 x (tanx) /tanx =
-cos^x
-cos^2 (0) = -1
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∙ 12y ago
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If f(x) cos(2x).cos(4x).cos(6x).cos(8x).cos(10x) then find the limit of 1 - f(x)35(sinx)2 as x tends to 0 (zero).?
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