For a quadratic equation y=Ax2+Bx+C, the line of symmetry is given by x=-B/2A
So for the equation y=-x2+x+3, B is 1 and A is -1, so the line of symmetry is
x=1/2
Is a parabola whose directrix is below its vertex.
y = 0That's the equation of the x-axis.Its slope is zero.
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y -4 = 3(x-3)y = 3x -5
That would be a linear equation.
At: x = 6
When x = -5
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
Vertical line of symmetry cuts through x = -4 - (sqrt of 3)
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.
-1
y=x2-12x+7
For the equation ax2-2x-3, the quadratic coefficients are:a=a,b=-2c=-3.The equation of the line of symmetry is:x= -b/2aAs we know that the line of symmetry is x=1,we get:1 = 2/2a, so2a = 2and a = 1.We get a bowl-shaped parabola, whose lowest point is (1,-4).
focus , directrix
The given equation is not that of a parabola since there are no powers of 2. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
This is called the 'standard form' for the equation of a parabola:y =a (x-h)2+vDepending on whether the constant a is positive or negative, the parabola will open up or down.
Without an equality sign it can not be considered to be an equation and the - or + value of 9x has not been given