y=x2-12x+7
-1
At: x = 6
Vertical line of symmetry cuts through x = -4 - (sqrt of 3)
Yes, but a parabola, itself, can have only a vertical line of symmetry.
the axis of symmetry
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.
At: x = 6
-1
When x = -5
Vertical line of symmetry cuts through x = -4 - (sqrt of 3)
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
For a quadratic equation y=Ax2+Bx+C, the line of symmetry is given by x=-B/2ASo for the equation y=-x2+x+3, B is 1 and A is -1, so the line of symmetry isx=1/2
Line of symmetry: x = 3
The line of symmetry located on a parabola is right down the center. A parabola is a U shape. Depending on the direction of the parabola it either has a x axis of symmetry or y axis of symmetry. You should have two equal sides of the parabola.
For the equation ax2-2x-3, the quadratic coefficients are:a=a,b=-2c=-3.The equation of the line of symmetry is:x= -b/2aAs we know that the line of symmetry is x=1,we get:1 = 2/2a, so2a = 2and a = 1.We get a bowl-shaped parabola, whose lowest point is (1,-4).
Yes. An ellipse (oval) has two lines of symmetry, but not a rotational symmetry. A parabola has one line and no rotation.
Yes, but a parabola, itself, can have only a vertical line of symmetry.